A) Frequency
B) Velocity
C) Time
D) Angular momentum
Correct Answer: A
Solution :
: As Planck constant \[(h)=\frac{energy}{frequency}\] and moment of inertia (I) \[=mass\times {{(radius\text{ }of\text{ }gyration)}^{2}}\] \[\therefore \] \[[h]=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{T}^{-1}}]}=[M{{L}^{2}}{{T}^{-1}}]\] and \[[I]=[M][{{L}^{2}}]=[M{{L}^{2}}{{T}^{0}}]\] Their corresponding ratio is \[\frac{[h]}{[I]}=\frac{[M{{L}^{2}}{{T}^{-1}}]}{[M{{L}^{2}}{{T}^{0}}]}=[{{T}^{-1}}]=[frequency]\]
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