question_answer

An aromatic compound A \[({{C}_{7}}{{H}_{9}}N)\] on reacting with \[NaN{{O}_{2}}/HCl\] at \[{{0}^{o}}C\] forms benzyl alcohol and nitrogen gas. The number of isomers possible for the compound A is

A)  \[5\]   

B)  \[7\]    

C)  \[3\]   

D)  \[6\]

Correct Answer: A

Solution :

: The possible isomers of benzyl amine are: 1. 2. 3. 4. 5.