A) \[100A\]
B) \[\frac{1}{20}A\]
C) \[2A\]
D) \[20A\]
Correct Answer: D
Solution :
: As \[\frac{{{I}_{p}}}{{{I}_{s}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] where subscripts p and s represent primary and secondary. \[\therefore \] \[{{I}_{s}}=\left( \frac{{{N}_{p}}}{{{N}_{s}}} \right){{I}_{p}}\] Here, \[{{I}_{p}}=1A,\,\,{{N}_{p}}=1000,\,{{N}_{s}}=50\] \[\therefore \] \[{{I}_{s}}=\left( \frac{1000}{50} \right)(1\,A)=20A\] Hence the output current of the transformer is 20 A.
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