question_answer

Acetophenone cannot be prepared easily starting from

A)  \[{{C}_{6}}{{H}_{5}}CH(OH)C{{H}_{3}}\]

B)  \[{{C}_{6}}{{H}_{5}}C{{H}_{3}}\]

C)  \[{{C}_{6}}{{H}_{5}}C\equiv CH\]

D)  \[{{C}_{6}}{{H}_{6}}\]

Correct Answer: B

Solution :

: [a] \[\underset{Methyl\,phenyl\,carbinol}{\mathop{{{C}_{6}}{{H}_{5}}CH(OH)C{{H}_{3}}}}\,\xrightarrow{[O]}\]    \[\underset{Acetophenone}{\mathop{{{C}_{6}}{{H}_{5}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\] [b] \[{{C}_{6}}{{H}_{5}}-COC{{H}_{3}}\xleftarrow{[O]}{{C}_{6}}{{H}_{5}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\] [c]   [d] \[\underset{Benzene}{\mathop{{{C}_{6}}{{H}_{6}}}}\,\xrightarrow[anhy.\,AlC{{l}_{3}}]{C{{H}_{3}}COCl}\underset{Acetophenone}{\mathop{{{C}_{6}}{{H}_{5}}COC{{H}_{3}}}}\,\]