A) \[300V\]
B) \[270V\]
C) \[30V\]
D) \[3V\]
Correct Answer: A
Solution :
: Electric potential due to a point charge Q at a distance r from it, is \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{r}\] Here, \[Q=3\text{ }nC=3\times {{10}^{-9}}C\] \[r=9cm=9\times {{10}^{-2}}m\] \[\therefore \] \[V=\frac{9\times {{10}^{9}}\times 3\times {{10}^{-9}}}{9\times {{10}^{-2}}}=300V\]
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