A) \[I={{I}_{0}}/5\]
B) \[I={{I}_{0}}\]
C) \[{{I}_{0}}/4\]
D) \[I={{I}_{0}}/6\]
Correct Answer: C
Solution :
: According to Mains law, the intensity of emergent polarized light from second polarizer is \[I={{I}_{0}}{{\cos }^{2}}\theta \] where \[\theta \] is the angle between pass axes of two polarizers and \[{{I}_{0}}\] is the intensity of polarized light after passing through the first polarizer. Here, \[\theta ={{60}^{{}^\circ }}\] \[\therefore \] \[I={{I}_{0}}{{\cos }^{2}}{{60}^{o}}={{I}_{0}}{{\left( \frac{1}{2} \right)}^{2}}=\frac{{{I}_{0}}}{4}\]
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