CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    An aero plane executes a horizontal loop at a speed of 720 km ph with its wings banked at\[{{45}^{o}}\]. What is the radius of the loop? Take \[g=10m{{s}^{-2}}\].

    A)  \[7.2km\]       

    B)  \[4km\]

    C)  \[2km\]         

    D)  \[4.5km\]

    Correct Answer: B

    Solution :

    : Here, Speed of the aeroplane, \[v=720\text{ }kmph\] \[v=720\times \frac{5}{18}m\,{{s}^{-1}}=200m\,{{s}^{-1}}\] Angle of banking, \[\theta ={{45}^{o}}\] Let R be the radius of the loop. As \[\tan \theta =\frac{{{v}^{2}}}{Rg}\] \[\therefore \] \[R=\frac{{{v}^{2}}}{g\,\tan \theta }=\frac{{{(200)}^{2}}}{10\times \tan {{45}^{o}}}=\frac{4\times {{10}^{4}}}{10\times 1}\] \[=4000m=4km\]


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