CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    A pipe of 30 cm long and open at both the ends produces harmonics. Which harmonic mode of pipe resonates a 1.1 kHz source? Given speed of sound in air \[=330m\text{ }{{s}^{-1}}\].

    A)  Third harmonic

    B)  Fifth harmonic

    C)  Second harmonic

    D)  Fourth harmonic

    Correct Answer: C

    Solution :

    : Here, Speed of sound, \[v=330\text{ }m\text{ }{{s}^{-1}}\] Length of pipe, \[L=30\,\,\,cm=30\times {{10}^{-2}}m\] In an open pipe (open at both ends), the  frequency of its nth harmonic is \[{{\upsilon }_{n}}=\frac{nv}{2L}\] where \[n=1,2,3,......\] \[\therefore \] \[n=\frac{2L{{\upsilon }_{n}}}{v}\] Let nth harmonic of open pipe resonate with 1.1 kHz source. i.e.,    \[{{\upsilon }_{n}}=1.1kHz=1.1\times {{10}^{3}}Hz\] \[\therefore \] \[n=\frac{2\times 30\times {{10}^{-2}}\times 1.1\times {{10}^{3}}}{330}=2\]


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