CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?

    A)  \[400\]

    B)  \[1600\]

    C)  \[1200\]

    D)  \[800\]

    Correct Answer: C

    Solution :

    : Since this pea plant is heterozygous for round shape, its genotype would be Rr. \[\begin{matrix}    Parents: & Rr & \times  & Rr  \\    {} & \downarrow  & (selfing) & {}  \\    \text{Progeny:} & RR & Rr & Rrrr  \\    {} & {} & {} & {}  \\ \end{matrix}\] Phenotypically, the ratio will be \[3:1\] i.e., only \[rr\] seedlings will show wrinkled phenotype, rest will show round shape. 1200  \[\to \]   Round shape (RR, Rr) 400  \[\to \]   Wrinkled (rr)


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