CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    Which one of the following has no unpaired electrons?

    A) \[{{O}_{2}}\]   

    B) \[O_{2}^{-}\]

    C) \[O_{2}^{+}\]   

    D) \[O_{2}^{2-}\]

    Correct Answer: D

    Solution :

    :
    Species Total electrons Configurations
    \[{{O}_{2}}\] \[16\] \[KK\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{z}})}^{2}}\] \[\pi {{(2{{p}_{x}})}^{2}}\,\pi {{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{1}}{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}\]
    \[O_{2}^{+}\] \[15\] \[KK\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{z}})}^{2}}\] \[\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{1}}\]
    \[O_{2}^{-}\] \[17\] \[KK\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{z}})}^{2}}\] \[\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}\]
    \[O_{2}^{2-}\] \[18\] \[KK\sigma {{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{z}})}^{2}}\] \[\pi {{(2{{p}_{x}})}^{2}}\pi {{(2{{p}_{y}})}^{2}}{{\pi }^{*}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}{{(2{{p}_{y}})}^{2}}\]
    So in \[O_{2}^{2-}\], all electrons are paired.


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