CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    Two fixed charges A and B of \[5\mu C\] each are separated by a distance of 6 m. C is the mid point of the line joining A and B. A charge Q of \[-5\mu C\] is shot perpendicular to the line joining A and B through C with a kinetic energy of 0.06 J. The charge Q comes to rest at a point D. The distance CD is

    A)  \[3m\]   

    B)  \[\sqrt{3}m\]

    C)  \[3\sqrt{3}m\]

    D)  \[4m\]

    Correct Answer: D

    Solution :

     \[4m\]


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