2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    Spheres of iron and lead having same mass are completely immersed in water. Density of lead is more than that of iron. Apparent loss of weight is \[{{W}_{1}}\]for iron sphere and \[{{W}_{2}}\]for lead sphere. Then \[\frac{{{W}_{1}}}{{{W}_{2}}}\] is

    A)  \[=1\]              

    B)  between 0 and 1

    C)  \[=0\]              

    D)  \[>1\]

    Correct Answer: D

    Solution :

     Density \[(\rho )=\frac{Mass(M)}{Volume(V)}\] \[\rho \propto \frac{1}{V}\]For the same mass. \[\therefore \] \[\frac{{{\rho }_{lead}}}{{{\rho }_{iron}}}=\frac{{{V}_{iron}}}{{{V}_{lead}}}\] As \[Plead>Piron\](Given) \[\therefore \] \[\frac{{{V}_{iron}}}{{{V}_{lead}}}>1\] ??.(i) Using law of floatation, For iron sphere \[{{W}_{1}}={{V}_{iron}}\,\,{{\rho }_{water}}g\]                     ?....(ii) For lead sphere \[{{W}_{2}}={{V}_{iron}}\,\,{{\rho }_{water}}g\] ?..(iii) Divide (ii) by (iii), we get \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{V}_{iron}}}{{{V}_{lead}}}>1\]  (Using (i))


You need to login to perform this action.
You will be redirected in 3 sec spinner