CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    The ratio of the magnetic dipole moment to the angular momentum of the electron in the 1st orbit of hydrogen atom is

    A)  \[\frac{e}{2m}\]  

    B)  \[\frac{e}{m}\]

    C)  \[\frac{2m}{e}\]

    D)  \[\frac{m}{e}\]

    Correct Answer: A

    Solution :

    : Magnetic dipole moment of the electron in the 1st orbit is \[M=\frac{eh}{4\pi m}\] ?...(i) Angular momentum of the electron in the 1st orbit is \[L=\frac{h}{2\pi }\] ???.(ii) Divide (i) by (ii), we get \[\frac{M}{L}=\frac{eh}{4\pi m}\times \frac{2\pi }{h}=\frac{e}{2m}\]


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