A) \[\frac{e}{2m}\]
B) \[\frac{e}{m}\]
C) \[\frac{2m}{e}\]
D) \[\frac{m}{e}\]
Correct Answer: A
Solution :
: Magnetic dipole moment of the electron in the 1st orbit is \[M=\frac{eh}{4\pi m}\] ?...(i) Angular momentum of the electron in the 1st orbit is \[L=\frac{h}{2\pi }\] ???.(ii) Divide (i) by (ii), we get \[\frac{M}{L}=\frac{eh}{4\pi m}\times \frac{2\pi }{h}=\frac{e}{2m}\]You need to login to perform this action.
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