2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    A planet moving around sun sweeps area \[{{A}_{1}}\] in 2 days, \[{{A}_{2}}\] in 3 days and \[{{A}_{3}}\]in 6 days.          Then the relation between \[{{A}_{1}},{{A}_{2}}\] and \[{{A}_{3}}\] is

    A)  \[3{{A}_{1}}=2{{A}_{2}}={{A}_{3}}\] 

    B)  \[2{{A}_{1}}=3{{A}_{2}}=6{{A}_{3}}\]

    C)  \[3{{A}_{1}}=2{{A}_{2}}=6{{A}_{3}}\]

    D)  \[6{{A}_{1}}=3{{A}_{2}}=2{{A}_{3}}\]

    Correct Answer: A

    Solution :

    : When a planet revolves around the sun, its areal velocity is constant. \[\therefore \] \[\frac{{{A}_{1}}}{{{t}_{1}}}=\frac{{{A}_{2}}}{{{t}_{2}}}=\frac{{{A}_{3}}}{{{t}_{3}}}\] \[\frac{{{A}_{1}}}{2}=\frac{{{A}_{2}}}{3}=\frac{{{A}_{3}}}{6}\] \[3{{A}_{1}}=2{{A}_{2}}={{A}_{3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner