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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    \[5mL\]of \[0.4N\text{ }NaOH\]is mixed with \[20mL\]of\[0.1N\text{ }HCl\]. The pH of the resulting solution will be

    A)  \[6\]      

    B)  \[7\]     

    C)  \[8\]      

    D)  \[5\]

    Correct Answer: B

    Solution :

    : Mill moles of \[NaOH=5\times 0.4=2\] Milli moles of \[HCl=20\times 0.1=2\] So 2 mill moles of \[NaOH\] and 2 mill moles of  \[HCl\] completely neutralise each other result. into a neutral solution \[(pH=7)\].


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