CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    The vapour pressures of two liquids A and B in their pure states are in ratio of\[1:2\]. A binary solution of A and 5 contains A and B in the mole proportion of \[1:2\]. The mole fraction of A in the vapour phase of the solution will be

    A)  \[0.33\]  

    B)  \[0.2\]

    C)  \[0.25\]  

    D)  \[0.52\]

    Correct Answer: A

    Solution :

    : Mole fraction of A in the vapour phase      \[=\frac{{{p}_{A}}}{{{p}_{A}}+{{p}_{B}}}=\frac{{{p}_{A}}}{{{p}_{A}}+2{{p}_{A}}}=\frac{1}{3}=0.33\]


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