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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    An aqueous solution containing \[6.5g\]of \[NaCl\] of 90% purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid \[NaOH\]. The volume of 1 M acetic acid required to neutralise \[NaOH\] obtained above is

    A)  \[1000c{{m}^{3}}\]  

    B)  \[2000c{{m}^{3}}\]

    C)  \[100c{{m}^{3~}}\]      

    D)  \[200c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    Weight of pure \[NaCl=6.5\times 0.9=5.85\text{ }g\] No. of equivalence of \[NaCl=\frac{5.85}{58.5}=0.1\] No. of equivalence of \[NaOH\] obtained \[=0.1\] Volume of 1 M acetic acid required for the neutralisation of \[NaOH=\frac{0.1\times 1000}{1}\] \[=100c{{m}^{3}}\]


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