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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    \[30cc\] of \[\frac{M}{3}HCl,\]\[20cc\]of \[\frac{M}{2}HN{{O}_{3}}\] and \[40cc\] of \[\frac{M}{4}NaOH\] solutions are mixed and the volume was made up to\[1\text{ }d{{m}^{3}}\]. The pH of the resulting solution is

    A) \[8\]                 

    B) \[2\]

    C) \[1\]                 

    D) \[3\]

    Correct Answer: B

    Solution :

    Total mill equivalents of \[{{H}^{+}}\] \[=30\times \frac{1}{3}+20\times \frac{1}{2}=20\] Total mill equivalents of \[O{{H}^{-}}\] \[=40\times \frac{1}{4}=10\] Milli equivalence of \[{{H}^{+}}\]left \[=20-10=10\] \[\therefore \] \[[{{H}^{+}}]=\frac{10}{1000}g\,ions/d{{m}^{3}}={{10}^{-2}}\] \[\therefore \] \[pH=2\]


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