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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    The oxidation state of Fe in the brown ring/ complex:  \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}\]is

    A)  \[+3\]             

    B)  \[0\]

    C)  \[+2\]             

    D) \[+1\]           

    Correct Answer: D

    Solution :

    Let   the   oxidation  state  of  \[Fe\]in \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}\] is x. \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\] \[\Rightarrow \] \[x+0+1=2\] \[\therefore \] \[x=+1\] Here \[NO\] exists as nitrosy! ion \[(N{{O}^{+}})\].


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