A) \[+4\]to \[0\]
B) \[+4\] to \[+2\]
C) \[+4\] to \[+6\]
D) \[+6\] to \[+4\]
Correct Answer: C
Solution :
Acidified \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] solution oxidises \[S{{O}_{2}}\] into \[C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\]. \[\overset{+4}{\mathop{3S{{O}_{2}}}}\,+{{K}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}\] \[+C{{r}_{2}}{{\overset{+6}{\mathop{(S{{O}_{4}})}}\,}_{3}}+{{H}_{2}}O\] Hence, oxidation state of sulphur changes from \[+4\] to \[+6\].
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