A) \[{{M}^{+}}{{X}^{-}}\]
B) \[{{M}^{+}}{{X}^{-}}(s)\]
C) \[MX\]
D) \[{{M}^{+}}{{X}^{-}}(g)\]
Correct Answer: B
Solution :
The Bom-Haber cycle takes place as follows
Hence, Z is \[{{M}^{+}}{{X}^{-}}(s)\].
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