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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    A Carnot engine takes heat from a reservoir at \[627{}^\circ \text{ }C\]and rejects heat to a sink at\[27{}^\circ C\]. Its efficiency will be:

    A)  3 / 5

    B)  1 / 3

    C)  2 / 3

    D)  200 / 209

    Correct Answer: C

    Solution :

    \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\therefore \] \[\eta =1-\frac{(27+273)}{(273+627)}\] \[=1-\frac{300}{900}=\frac{600}{900}=\frac{2}{3}\]


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