CET Karnataka Medical CET - Karnataka Medical Solved Paper-2004

  • question_answer
    A bullet moving with a speed of \[100\text{ }m{{s}^{-1}}\] can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be:

    A)  6

    B)  10

    C)  4

    D)  8

    Correct Answer: D

    Solution :

    Let the thickness of each plank is d. From equation of motion\[{{\upsilon }^{2}}={{u}^{2}}+2\]as ...(1) Ist case; \[s=2d,u=100\,m{{s}^{-1}},\upsilon =0\] \[\therefore \] \[0={{(100)}^{2}}+2a\times 2d\] \[\Rightarrow \] \[4ad=-100\times 100\] \[\Rightarrow \] \[a=-\frac{100\times 100}{4d}\] \[\therefore \] \[a=-\frac{2500}{d}\] ?(2) (- ve sign stands for retardation) lInd case; Let the bullet with double the previous -speed will penetrate n planks of equal thickness d. Now, \[\upsilon =0,u=200\,m{{s}^{-1}},a=-\frac{2500}{a},s=nd\] Using equation (1) again, we have \[0={{(200)}^{2}}-2\times \frac{2500}{d}\times nd\] \[\Rightarrow \] \[n=\frac{200\times 200}{2\times 2500}=8\]


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