CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    The temperature of a gas contained in a closed vessel of constant volume increases by \[{{1}^{o}}C\] when the pressure of the gas is increased by 1%. The initial temperature of the gas is

    A) 100 K                                    

    B) \[{{273}^{o}}C\]

    C) \[{{100}^{o}}C\]               

    D) 200 K

    Correct Answer: A

    Solution :

    According to Gay Lussac's law \[p\propto T\] \[\therefore \]  \[\frac{dp}{p}\times 100=\frac{dT}{T}\times 100\]                 \[1=\frac{1}{T}\times 100\] \[\Rightarrow \]               \[T=100\,K\]


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