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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    A body of mass \[x\] kg is moving with a velocity of \[100\,\,m{{s}^{-1}}\].  Its de-Broglie wavelength is\[6.62\times {{10}^{-35}}m\]. Hence, \[x\] is \[(h=6.62\times {{10}^{-34}}Js)\]

    A)  0.1 kg                                  

    B)  0.25 kg

    C)  0.15 kg                                

    D)  0.2 kg

    Correct Answer: A

    Solution :

    \[\lambda =\frac{h}{mv}\]     \[=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-34}}\times 100}\]      \[=0.1\,\,kg\]


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