A) \[36\,m\]
B) \[32\,m\]
C) \[100\,\,m\]
D) \[64\,\,m\]
Correct Answer: C
Solution :
Given, \[s=48t-16{{t}^{2}}\] \[\Rightarrow \] \[\frac{ds}{dt}=48-32t\] At the greatest height, \[v=\frac{dx}{dt}=0\] \[\Rightarrow \] \[48-32t=0\] \[\Rightarrow \] \[t=\frac{3}{2}\] \[\therefore \] \[s=48\times \frac{3}{2}-16{{\left( \frac{3}{2} \right)}^{2}}\] \[=36m\] \[\therefore \] Total height \[=64+36=100m\]You need to login to perform this action.
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