A) \[22.4\,\,d{{m}^{3}}\]
B) \[44.8\,\,d{{m}^{3}}\]
C) \[67.2\,\,d{{m}^{3}}\]
D) \[11.2\,\,d{{m}^{3}}\]
Correct Answer: C
Solution :
\[\underset{1\,\,mol}{\mathop{F{{e}_{2}}C{{O}_{3}}}}\,+\underset{3\,\,mol}{\mathop{3CO}}\,\xrightarrow{{}}2Fe+3C{{O}_{2}}\] Volume of 1 mole carbon monoxide = 22.4 L (at STP) 1 mole of ferric oxide is reduced by = 3 moles of CO \[=3\times 22.4\,L\] of \[CO\] \[=67.2\,\,d{{m}^{3}}\]of \[CO\]
You need to login to perform this action.
You will be redirected in
3 sec
