CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    How many times more intense is a 60 dB sound than a 30 dB sound?

    A)  1000                                     

    B)  2

    C)  100                                       

    D)  4

    Correct Answer: A

    Solution :

                    \[L=10\,{{\log }_{10}}\frac{I}{{{I}_{0}}}\]                 \[60=10\,{{\log }_{10}}\frac{{{I}_{1}}}{{{I}_{0}}}\] \[\Rightarrow \]               \[\Rightarrow \frac{{{I}_{1}}}{{{I}_{0}}}={{10}^{6}}\]                                        ... (i) Similarly,                 \[30=10\,{{\log }_{10}}=\frac{{{I}_{2}}}{{{I}_{0}}}\]                 \[\frac{{{I}_{2}}}{{{I}_{0}}}={{10}^{3}}\]                                 ... (ii) Dividing Eq. (i) by Eq. (ii), we get                 \[\frac{{{I}_{1}}}{{{I}_{2}}}=1000\]


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