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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    Equation of the tangent and the normal drawn at the point (6, 0) on the ellipse\[\frac{{{x}^{2}}}{36}+\frac{{{y}^{2}}}{9}=1\]respectively are:

    A) \[x=6,y=0\]                        

    B)  \[y+x-6=0,y-x+6=0\]

    C)  \[x=0,y=3\]

    D)  \[x=-6,y=0\]

    Correct Answer: A

    Solution :

    The equation of the tangent at \[(6,0)\]is \[\frac{x{{x}_{1}}}{{{a}^{2}}}+\frac{y{{y}_{1}}}{{{b}^{2}}}=1\Rightarrow \frac{6x}{36}+\frac{y(0)}{9}=1\] \[\frac{6x}{36}=1\Rightarrow x=6\]and the equation of the normal is \[y=0.\]


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