A) \[2KT\]
B) \[\frac{1}{2}RT\]
C) \[\frac{3}{2}RT\]
D) \[\frac{2}{3}KT\]
Correct Answer: C
Solution :
The molecules of a gas are in random motion always. According to the kinetic energy of gases, translational kinetic energy of the gas molecules for one mole of a gas is\[=\frac{3}{2}RT\]
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