2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    \[f:R\to R\]is a function defined by\[f(x)=10x-7.\]If \[g={{f}^{-1}}\]then \[g(x)=\]

    A)  \[\frac{1}{10{{x}^{-7}}}\]                            

    B)  \[\frac{1}{10x+7}\]

    C)  \[\frac{x+7}{10}\]                          

    D)  \[\frac{x-7}{10}\] 

    Correct Answer: C

    Solution :

    Let \[f(x)=y.\]Then \[10x-7=y\] \[\Rightarrow \] \[x=\frac{y+7}{10}\] Now, \[F(x)=y\Rightarrow {{f}^{-1}}(y)=x=\frac{y+7}{10}.\]So \[f'(x)=\frac{x+7}{10}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner