A) \[(G,*),ab=ac\Rightarrow b=c\forall a,b,c\in C\]
B) In an abelian group,\[{{(ab)}^{2}}={{a}^{2}}{{b}^{2}},\forall a,b,\in G\]
C) Cube roots of unity forms an additive abelian group
D) In a group of even order, there exist an element other than identity which is its own inverse.
Correct Answer: C
Solution :
We know that as the cube roots of unity do not satisfy the properties of an abelian group, therefore option 'c' is false.
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