CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    The length of the tangent drawn from any point on the circle\[{{x}^{2}}+{{y}^{2}}+2fy+\lambda =0\]to the circle\[{{x}^{2}}+{{y}^{2}}+2fy+\mu =0,\]where\[\mu >\lambda >0\],is

    A)  \[\sqrt{\mu -\lambda }\]            

    B)         \[\sqrt{\mu +\lambda }\]

    C)  \[\sqrt{{{\mu }^{2}}-{{\lambda }^{2}}}\]              

    D)         \[\mu +\lambda \]

    E)  \[\mu -\lambda \]

    Correct Answer: A

    Solution :

    Let\[({{x}_{1}},{{y}_{1}})\]be the point on the circle \[{{x}^{2}}+{{y}^{2}}+2fy+\lambda =0\] \[\Rightarrow \]               \[x_{1}^{2}+y_{1}^{2}+2f{{y}_{1}}+\lambda =0\] \[\Rightarrow \]               \[x_{1}^{2}+y_{1}^{2}+2f{{y}_{1}}=-\lambda \]       ...(i) Now, the length of tangent from the point \[({{x}_{1}},{{y}_{1}})\]to the circle\[{{x}^{2}}+{{y}^{2}}+2fy+\mu =0\]is                 \[=\sqrt{(x_{1}^{2}+y_{1}^{2}+2f{{y}_{1}})+\mu }\]                 \[=\sqrt{\mu -\lambda }\]                           [from Eq. (i)]


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