CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If \[\frac{-\pi }{2}<\theta <\frac{\pi }{2}\]and\[\theta \ne \pm \frac{\pi }{4},\]then the value of\[\cot \left( \frac{\pi }{4}+\theta  \right)\cot \left( \frac{\pi }{4}-\theta  \right)\]is

    A)  0                            

    B)         \[-1\]

    C)  1                            

    D)         \[-2\]

    E)  2

    Correct Answer: C

    Solution :

    \[\cot \left( \frac{\pi }{4}+\theta  \right).\cot \left( \frac{\pi }{4}-\theta  \right)\] and        \[\theta \in \left( -\frac{\pi }{2},\frac{\pi }{2} \right)\tilde{\ }\left\{ \pm \frac{\pi }{4} \right\}\] \[=\tan \left( \frac{\pi }{2}-\frac{\pi }{4}-\theta  \right).\tan \left( \frac{\pi }{2}-\frac{\pi }{4}+\theta  \right)\] \[=\tan \left( \frac{\pi }{4}-\theta  \right).\tan \left( \frac{\pi }{4}+\theta  \right)\] \[=\frac{\tan \frac{\pi }{4}-\tan \theta }{1+\tan \frac{\pi }{4}.\tan \theta }.\frac{\tan \frac{\pi }{4}+\tan \theta }{1-\tan \frac{\pi }{4}.\tan \theta }\] \[=\frac{1-\tan \theta }{1+\tan \theta }.\frac{1+\tan \theta }{1-\tan \theta }\]


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