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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    The total revenue in rupees received from the sale of x units of a product is given by\[R(x)=13{{x}^{2}}+26x+15\]. Then, the marginal revolution rupees, when\[x=15\]is

    A)  116                       

    B)  126  

    C)  136                       

    D)         416

    E)  146

    Correct Answer: D

    Solution :

    Given, \[R(x)=13{{x}^{2}}+26x+15\] Now, the marginal revenue \[=\frac{d}{dx}(R(x))\]                 \[=\frac{d}{dx}(13{{x}^{2}}+26x+15)\]                 \[=26x+26\] Therefore, marginal revenue at \[(x=15)\] \[=26\times 15+26\] \[=390+26=416\]


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