CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A solid compound contains X, Y and Z atoms in a cubic lattice with X atom occupying the comers. Y atoms in the body centred positions and Z atoms at the centres of faces of the unit cell. What is the empirical formula of the compound?

    A) \[X{{Y}_{2}}{{Z}_{3}}\]                                  

    B) \[XY{{Z}_{3}}\]

    C) \[{{X}_{2}}{{Y}_{2}}{{Z}_{3}}\]                   

    D)         \[{{X}_{8}}Y{{Z}_{6}}\]

    E)  \[XYZ\]

    Correct Answer: B

    Solution :

    Since atom X is present at corner and one comer is shared by eight unit cells, number of X atoms per unit cell \[=\frac{1}{8}\times 8=1\] Atom Y is present at body centred position and used by only one unit cell. So, number of Y atoms per unit cell = 1 Atom Z is present at the centre of each face, so shared by two unit cells, thus number of Z atoms per unit cell\[=\frac{1}{2}\times 6=3\] Hence, the formula of compound\[=XY{{Z}_{3}}\]


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