CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    The flux linked with a circuit is given by \[\phi ={{t}^{3}}+3t-7\]. The graph between time (\[x-\]axis) and induced emf (y-axis) will be a

    A)  straight line through the origin

    B)  straight line with positive intercept

    C)  straight line with negative intercept

    D)  parabola through the origin

    E)  parabola not through the origin

    Correct Answer: E

    Solution :

    \[\phi ={{t}^{3}}+3t-7\] \[\therefore \]Induced emf                 \[e=-\frac{d\phi }{dt}=-(3{{t}^{2}}+3)=-3{{t}^{2}}-3\] At \[t=0;\,\,e=-3V\] Therefore, shape of graph will be a parabola not through origin.


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