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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Let\[P(-7,1,-5)\]be a point on a plane and let\[O\]be the origin. If OP is normal to the plane, then the equation of the plane is

    A)  \[7x-y+5z+75=0\]

    B)  \[7x+y-5z+73=0\]

    C)  \[7x+y+5z+73=0\]

    D)  \[7x-y-5z+75=0\]

    E)  \[7x-y-5z+73=0\]

    Correct Answer: A

    Solution :

    Equation of any plane passing through\[(-7,1,-5)\]is \[a(x+7)+b(y-1)+c(z+5)=0\]                            ?.(i) The DRs of normal to above plane are \[a=-7,b=1,c=-5\] \[\therefore \]From Eq. (i), we get \[-7(x+7)+1(y-1)-5(z+5)=0\] \[\Rightarrow \]               \[-7x+y-5z-75=0\] \[\Rightarrow \]               \[7x-y+5z+75=0\]


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