CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    The equation of the plane perpendicular to the line\[\frac{x-1}{1}=\frac{y-2}{-1}=\frac{z+1}{2}\]and passing through the point (2, 3, 1) is

    A)  \[\overrightarrow{r}.(\hat{i}+\hat{j}+2\hat{k})=1\]

    B)  \[\overrightarrow{r}.(\hat{i}-\hat{j}+2\hat{k})=1\]

    C)  \[\overrightarrow{r}.(\hat{i}-\hat{j}+2\hat{k})=7\]

    D)  \[\overrightarrow{r}.(\hat{i}+\hat{j}-2\hat{k})=10\]

    E)  None of the above

    Correct Answer: B

    Solution :

    The given line is parallel to the vector \[\overrightarrow{n}=\hat{i}-\hat{j}+2\hat{k}\].The required plane passing through the point\[(2,3,1)\]ie,\[2\hat{i}+3\hat{j}+\hat{k}\]and is  perpendicular to the vector \[n=\hat{i}-\hat{j}+2\hat{k}\]. \[\therefore \] Its equation is                 \[[(\overrightarrow{r}-(2\hat{i}+3\hat{j}+\hat{k})].(\hat{i}-\hat{j}+2\hat{k})=0\] \[\Rightarrow \]                               \[\overrightarrow{r}.(\hat{i}-\hat{j}+2\hat{k})=1\]         


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