CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    In an equilateral triangle of side\[2\sqrt{3},\]the circumradius is

    A)  1 cm                                     

    B)  \[\sqrt{3}cm\]

    C)  2 cm                     

    D)         \[2\sqrt{3}cm\]

    E)  4cm

    Correct Answer: C

    Solution :

    \[R=\frac{a}{2\sin A}\] \[\Rightarrow \]               \[R=\frac{2\sqrt{3}}{2\sin 60{}^\circ }=2\,cm\]


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