A) \[\frac{1}{2}\frac{YA}{l}{{x}^{2}}\]
B) \[\frac{1}{3}\frac{YA}{l}{{x}^{2}}\]
C) \[\frac{1}{2}\frac{Yl}{A}{{x}^{2}}\]
D) \[\frac{1}{2}\frac{YA}{{{l}^{2}}}{{x}^{2}}\]
E) \[\frac{1}{2}\frac{A}{Yl}{{x}^{2}}\]
Correct Answer: A
Solution :
Energy stored in the wire \[U=\frac{1}{2}Y\times {{(strain)}^{2}}\times volume\] Or \[U=\frac{1}{2}Y\times {{\left( \frac{x}{l} \right)}^{2}}\times Al\] Or \[U=\frac{1}{2}\frac{Y{{x}^{2}}}{l}\times A\] Or \[U=\frac{1}{2}\frac{YA}{l}{{x}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
