A) \[\frac{5}{3}\]
B) \[4\]
C) \[\frac{81}{625}\]
D) \[16\]
E) \[\frac{1}{2}\]
Correct Answer: D
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{25}{9}\] Or \[{{\left( \frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}} \right)}^{2}}=\frac{25}{9}\] where a denotes amplitude. Or \[\frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}}=\frac{5}{3}\] Or \[\frac{{{a}_{1}}}{{{a}_{2}}}=4\] As, \[{{(amplitude)}^{2}}\propto intensity\] Hence, \[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)}^{2}}=16\]
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