CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    The value of\[\left( \frac{^{50}{{C}_{0}}}{1}+\frac{^{50}{{C}_{2}}}{3}+\frac{^{50}{{C}_{4}}}{5}+.... \right.\]\[\left. +\frac{^{50}{{C}_{50}}}{51} \right)\]is

    A)  \[\frac{{{2}^{50}}}{51}\]                              

    B)         \[\frac{{{2}^{50}}-1}{51}\]

    C)  \[\frac{{{2}^{50}}-1}{50}\]          

    D)         \[\frac{{{2}^{51}}-1}{51}\]

    E)  \[\frac{{{2}^{51}}-1}{50}\]

    Correct Answer: A

    Solution :

    \[\left( \frac{^{50}{{C}_{0}}}{1}+\frac{^{50}{{C}_{2}}}{3}+\frac{^{50}{{C}_{4}}}{5}+....+\frac{^{50}{{C}_{50}}}{51} \right)\] \[=\frac{1}{1}+\frac{50\times 49}{3\times 2!}+\frac{50\times 49\times 48\times 47}{5\times 4!}+....\] \[=\frac{1}{51}\left( 51+\frac{51\times 50\times 49}{3!}+\frac{\begin{align}   & 51\times 50\times 49 \\  & \times 48\times 47 \\ \end{align}}{5!}+.... \right)\] \[=\frac{1}{51}{{(}^{51}}{{C}_{1}}{{+}^{51}}{{C}_{3}}{{+}^{51}}{{C}_{5}}+....)\] \[=\frac{1}{51}{{.2}^{51-1}}=\frac{{{2}^{50}}}{51}\]


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