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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    Two identical cells send the same current in\[3\,\Omega \]. resistance, whether connected in series or in parallel. The internal resistance of the cell should be:

    A)  \[1\,\Omega \]               

    B)         \[3\,\Omega \]

    C)  \[\frac{1}{2}\,\Omega \]            

    D)         \[3.5\,\Omega \]

    E)  \[\frac{3}{2}\,\Omega \]

    Correct Answer: B

    Solution :

    From ohms law \[I=\frac{2E}{2r+R}\] In parallel combination of two cells, the current through the external resistance r will be                 \[I=\frac{E}{\frac{r}{2}+R}=\frac{2E}{2r+R}\] If\[I=I\]If then \[2r+R=r+2R\] \[\Rightarrow \]               \[R=r=3\,\Omega \]


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