CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    \[\int\limits_{-10}^{10}{\log \left( \frac{a+x}{a-x} \right)}dx\]is equal to:

    A)  0                            

    B)         \[-2\log (a+10)\]

    C)  \[2\log \left( \frac{a+10}{a-10} \right)\]

    D)         \[2\log (a+10)\]

    E)  \[2\]

    Correct Answer: A

    Solution :

    \[\int_{-10}^{10}{\log \left( \frac{a+x}{a-x} \right)}dx\] Let \[f(x)=\log \left( \frac{a+x}{a-x} \right)\] \[\Rightarrow \] \[f(-x)=\log \left( \frac{a-x}{a+x} \right)=-\log \left( \frac{a+x}{a-x} \right)\] \[=-f(x)\] \[\Rightarrow \]               \[f(x)\]is an odd \[\therefore \]  \[\int_{-10}^{10}{f(x)}dx=0\]


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