CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2006

  • question_answer
    The value of \[\left| \begin{matrix}    \cos (x-a) & \cos (x+a) & \cos x  \\    \sin (x+a) & \sin (x-a) & \sin x  \\    \cos a\tan x & \cos a\cot x & \cos ec2x  \\ \end{matrix} \right|\]is equal to:

    A)  1                                            

    B) \[sin\text{ }a\text{ }cos\text{ }a\]           

    C)         0                            

    D)        \[sin\text{ }x\text{ }cos\text{ }x\]

    E)  \[cosec\text{ }2x\]

    Correct Answer: C

    Solution :

    \[\left| \begin{matrix}    \cos (x-a) & \cos (x+a) & \cos x  \\    \sin (x+a) & \sin (x-a) & \sin x  \\    \cos a\tan x & \cos a\cos x & \cos ec2x  \\ \end{matrix} \right|\] \[=\left| \begin{matrix}    \cos (x-a)+\cos (x+a) & \cos (x+a)  \\    \sin (x+a)+\sin (x-a) & \sin (x-a)  \\    \cos a(\tan x+\cot x) & \cos a\,\cot x  \\ \end{matrix} \right.\]\[\left. \begin{matrix}    \cos x  \\    \sin x  \\    \cos ec2x  \\ \end{matrix} \right|\] \[=\left| \begin{matrix}    2\cos x\cos a & \cos (x+a) & \cos x  \\    2\sin x\cos a & \sin (x-a) & \sin x  \\    \cos a\left( \frac{{{\tan }^{2}}x+1}{\tan x} \right) & \cos a\cot x & \cos ec2x  \\ \end{matrix} \right|\] \[=2\cos a\left| \begin{matrix}    \cos x & \cos (x+a) & \cos x  \\    \sin x & \sin (x-a) & \sin x  \\    \frac{1+{{\tan }^{2}}x}{2\tan x} & \cos a\cot x & \cos ec2x  \\ \end{matrix} \right|\] \[=2\cos a\left| \begin{matrix}    \cos x & \cos (x+a) & \cos x  \\    \sin x & \sin (x-a) & \sin x  \\    \cos ec2x & \cos a\,\cot x & \cos ec2x  \\ \end{matrix} \right|\] \[=2\cos a\times 0=0\]


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