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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If the distance of the point (1, 1, 1) from the origin is half its distance from the plane \[x+y+z+k=0,\]then k is equal to:

    A)  \[\pm \,3\]                                       

    B)  \[\pm 6\]

    C)  \[-3,9\]               

    D)         \[3,-9\]

    E)  3, 9

    Correct Answer: D

    Solution :

    Distance  of a  point  (1, 1, 1)  from\[x+y+z+k=0\]is \[\left| \frac{1+1+1+k}{\sqrt{3}} \right|\] According to question,                 \[\left| \frac{3+k}{\sqrt{3}} \right|=\pm 2\sqrt{3}\] \[\Rightarrow \]               \[k=3,-9\]


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