A) \[\frac{r}{2}\]
B) \[\frac{r}{\sqrt{2}}\]
C) \[\frac{r}{\sqrt{3}}\]
D) \[\frac{r}{\sqrt{7}}\]
E) \[\sqrt{3r}\]
Correct Answer: C
Solution :
\[{{E}_{1}}=\frac{1}{{{h}^{2}}}\] ...(1) and \[{{E}_{2}}=\frac{I\cos \theta }{\left( \sqrt{{{h}^{2}}+{{r}^{2}}} \right)}\] ...(2) \[=\frac{I\times h}{{{({{h}^{2}}+{{r}^{2}})}^{3/2}}}\] \[\therefore \] \[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{1}{8}=\frac{{{h}^{3}}}{{{({{h}^{2}}+{{r}^{2}})}^{3/2}}}\] \[\Rightarrow \]\[{{({{h}^{2}}+{{r}^{2}})}^{1/2}}=2h\]\[\Rightarrow \]\[{{h}^{2}}=\frac{r}{\sqrt{3}}\]You need to login to perform this action.
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