CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The equation of the plane through the point (1, 2, 3),\[(-1,4,\text{ }2)\]and (3, 1,1) is:

    A)  \[5x+y+12z-23=0\]

    B)  \[5x+6y+\text{ }2z-23=0\]

    C)  \[x+\text{ }6y+\text{ }2z-13=0\]

    D)  \[x+y+2-13=0\]

    E) \[5x+y+z-23=0\]

    Correct Answer: B

    Solution :

    Equation of plane through (1, 2, 3) is \[a(x-1)+b(y-2)+c(z-3)=0\]              ...(i) It passes through (-1, 4, 2) and (3, 1, 1) \[-2a+2b-c=0\]            ...(ii) and          \[2a-b-2c=0\]             ...(iii) From Eqs. (ii) and (iii) \[\frac{a}{-5}=\frac{b}{-6}=\frac{c}{-2}\] \[\therefore \]Equation of plane is \[-5x-6y-2z+5+12+6=0\] \[\Rightarrow \]               \[5x+6y+2z-23=0\]


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