A) \[{{I}_{2}}+10HN{{O}_{3}}\xrightarrow{{}}2HI{{O}_{3}}+10N{{O}_{2}}\]\[+4{{H}_{2}}O\]
B) \[3Cu+8HN{{O}_{3}}\xrightarrow{{}}3Cu{{(N{{O}_{3}})}_{2}}\]\[+2NO+4{{H}_{2}}O\]
C) \[4Zn+10HN{{O}_{3}}\xrightarrow[{}]{{}}4Zn{{(N{{O}_{3}})}_{2}}\]\[+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
D) \[N{{O}_{3}}+3F{{e}^{2+}}+4{{H}^{+}}\xrightarrow[{}]{{}}NO\]\[+3F{{e}^{3+}}+2{{H}_{2}}O\]
E) \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{5}}\xrightarrow{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\]
Correct Answer: E
Solution :
In the reaction, \[2HN{{O}_{3}}+{{P}_{2}}{{O}_{5}}\xrightarrow{{}}2HP{{O}_{3}}+{{N}_{2}}{{O}_{5}}\] \[HN{{O}_{3}}\]does not behave as an oxidizing agent. Because in this reaction\[{{P}_{2}}{{O}_{5}}\]shows dehydrating properties. It removes water molecule from\[HN{{O}_{3}}\].
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